Question

Question #b46bf

Answer 1

`cos(2arcsin(5/13))=119/169`

Explanation:

Applying the double angle identity `cos(2theta) = 1-2sin^2(theta)`, we get

`cos(2arcsin(5/13)) = 1-2sin^2(arcsin(5/13))`

`=1 -2(sin(arcsin(5/13))^2`

`=1 - 2(5/13)^2`

`=1-50/169`

`=119/169`