Question #a50b9

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Answer 1 · 2016-10-22T20:32:55

$? = 361$ $? = 361$

We start by distributing the left hand side, letting $? = x$ $? = x$

$12 \sqrt{36} + 3 \sqrt{36} - 8 \sqrt{36} - 2 \sqrt{36} = \sqrt{x} + 11$ $12sqrt(36) + 3sqrt(36) - 8sqrt(36) - 2sqrt(36) = sqrt(x) + 11$

$12 (6) + 3 (6) - 8 (6) - 2 (6) = \sqrt{x} + 11$ $12(6) + 3(6) - 8(6) - 2(6) = sqrt(x) + 11$

$30 = \sqrt{x} + 11$ $30 = sqrt(x) + 11$

$30 - 11 = \sqrt{x}$ $30 - 11 =sqrt(x)$

$19 = \sqrt{x}$ $19 = sqrt(x)$

Now, square both sides to get rid of the square root.

${(\sqrt{x})}^{2} = 19^{2}$ $(sqrt(x))^2 = 19^2$

$x = 361$ $x = 361$

Hopefully this helps!