Question #0c37e

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Answer 1 · 2017-02-15T11:08:28

Given

$"Total pressure of moisture and He "P=1.20atm$

$"Partial pressure of sat.vapour at" 45^@C=(f)=71.88"torr"=71.88/760atm~~0.095atm$

$"Temperature "T=(45+273)=328K$

$"Pressure of He"=p_(He)=1.20-0.95=1.105atm$

$"Mass of He"=0.586g$

$n_(He)=(0.586g)/(4g"/mol")=0.1465mol$

Now by ideal gas equation

$p_(He)V_(He)=n_(He)RT$

$V_(He)=(0.1465molxx0.082LatmK^-1mol^-1xx328K)/(1.105atm)$

$~~3.57L$