Question #197e4

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Chuck W.
Nov 4, 2016

Calculate the concentration of #H^+# and then take the negative base-10 logarithm to get the pH.

Explanation:

The balanced reaction is
#CH_3COOH(aq) harr H^+(aq) + CH_3COO^(-)(aq)#

If 5% of the acid ionizes, then the concentration of #H^+# is
#[H^+]=2.0M times 0.05 = 0.1M#

The ph is then

pH = #-log[H^+] = -log(0.1) = 1.0#

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