Question #da2fb

1 Answer
Oct 31, 2016

2. 9
4. 10

Explanation:

I'll do questions 2 and 4.

2. We need to factor the numbers within the square roots.

=>5sqrt(4 xx 3) - 2sqrt(25 xx 3) + 3sqrt(9 xx 3)

=>5(2)sqrt(3) - 2(5)sqrt(3) + 3(3)sqrt(3)

=>10sqrt(3) - 10sqrt(3) + 9sqrt(3)

=>9sqrt(3)

The numerical coefficient is 9.

4. This is a trinomial factoring problem. When we want to factor a trinomial of the form y = ax^2+bx + c, a!=1, 0, we need to find two numbers that multiply to ac and that add to b.

=>10r^2 - 8r + 35r - 28

=>2r(5r - 4) + 7(5r - 4)

=>(2r + 7)(5r - 4)

The value of a+ b + c + d is 2 + 7 + 5 - 4 = 10

Hopefully this helps!