Question

A `300*mL` volume gas at `0.500*atm` in a piston, is compressed to `0.750*atm`. What is the new volume?

Answer 1

`V_2=200*mL`

Explanation:

Old `"Boyle's Law"` holds that for a given quantity of gas, at constant temperature, `Pprop1/V`, and thus `PV=k`, where `k` is some constant........

And it follows that `P_1V_1=P_2V_2`, and.........

`V_2=(P_1V_1)/P_2`, which clearly has the units of volume as required.....

Here `V_2=(300*mLxx0.500*atm)/(0.750*atm)`

`=200*mL`, volume is reduced as expected..........