A molar volume of gas whose mass is $222 \cdot g \cdot m o l^{- 1}$ $222gmol^-1$ is confined in a $22.4 \cdot L$ $22.4L$ container. What is the density of the gas in $g \cdot L^{- 1}$ $gL^-1$ ?

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A molar volume of gas whose mass is $222 \cdot g \cdot m o l^{- 1}$ $222gmol^-1$ is confined in a $22.4 \cdot L$ $22.4L$ container. What is the density of the gas in $g \cdot L^{- 1}$ $gL^-1$ ?

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Answer 1 · 2016-11-06T17:42:36

At $STP$ $"STP"$ , one mole of ideal gas occupies occupies a volume of $22.4 \cdot L$ $22.4*L$ . So.......

Explanation:

$ρ, density = \frac{Mass}{Volume}$ $rho, "density"="Mass"/"Volume"$ .

If we assume that the gas behaves ideally (a safe assumption!) then,

$ρ = \frac{222 \cdot g \cdot m o l^{- 1}}{22.4 \cdot L \cdot m o l^{- 1}} ≅ 10 \cdot g \cdot L^{- 1}$ $rho=(222*g*mol^-1)/(22.4*L*mol^-1)~=10*g*L^-1$ .

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A molar volume of gas whose mass is $222 \cdot g \cdot m o l^{- 1}$ $222gmol^-1$ is confined in a $22.4 \cdot L$ $22.4L$ container. What is the density of the gas in $g \cdot L^{- 1}$ $gL^-1$ ?

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Explanation:

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A molar volume of gas whose mass is $222 \cdot g \cdot m o l^{- 1}$ $222gmol^-1$ is confined in a $22.4 \cdot L$ $22.4L$ container. What is the density of the gas in $g \cdot L^{- 1}$ $gL^-1$ ?