How do you solve #x^4+3x^3-4x^2+12=0#?

1 Answer
Oct 27, 2017

Since this polynomial has no easily determined solutions and no further clarification was provided, I've employed an "engineer"-type solution to clear out this question.

Explanation:

Note that I dropped the #=0# portion of the given equality to make it a polynomial function.

Using a graphing package I can establish the x-intercepts at approximately #x=-1.38# and #x=-3.831# (there are only 2 intercepts)
Based on these values #{(f(x) > 0,"if " x < -3.831),(f(x) < 0,"if "x in (-3.831,-1.38)),(f(x) > 0,"if "x > -1.38):}#

We could now test using values #x in{-5,-2,0}#
but using the graph, this is not really necessary.

Here is the graph at a moderate scale (I had to blow it up significantly to get approximations for the x-intercept values):
enter image source here