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Question #f8416

1 Answer

Jan 12, 2017

He is running at 4.5 m/s

Explanation:

Since kinetic energy is $\frac{1}{2} m v^{2}$ $1/2mv^2$ , we can find his speed as follows:

$K = \frac{1}{2} m v^{2}$ $K=1/2mv^2$

$v^{2} = 2 \frac{K}{m}$ $v^2=2K/m$

$v = \sqrt{\frac{2 K}{m}} = \sqrt{\frac{(2) (734)}{72.5}} = 4.5 \frac{m}{s}$ $v=sqrt ((2K)/m) = sqrt (((2)(734))/72.5)=4.5 m/s$

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