Question #3c3a8

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Answer 1 · 2017-08-01T17:24:29

$520$ $"kJ"$

The formula for kinetic energy is $E_("K") = frac(1)(2) m v^(2)$ ; where $m$ is the mass of an object and $v$ is its velocity.

Let's substitute the given values into the formula:

$Rightarrow E_("K") = frac(1)(2) cdot 1612$ $"kg" cdot (95.4 " km/h")^(2)$

First, let's express the units $95.4$ $"km/h"$ in terms of $"m s"^(- 1)$ :

$Rightarrow E_("K") = 806$ $"kg" cdot (95.4 cdot frac(1000)(3600) "m s"^(- 1))^(2)$

$Rightarrow E_("K") = 806$ $"kg" cdot 645.16$ $"m"^(2) cdot "s"^(- 2)$

$Rightarrow E_("K") = 519,998.96$ $"kg" cdot "m"^(2) cdot "s"^(- 2)$

Then, let's express this kinetic energy in joules:

$Rightarrow E_("K") = 519,998.96$ $"J"$

Now, we must express the kinetic energy in kilojoules.

So let's divide the value by $10^(3)$ :

$Rightarrow E_("K") = frac(519,998.96)(10^(3))$ $"kJ"$

$therefore E_("K") = 519.99896$ $"kJ"$

Therefore, the kinetic energy of this vehicle is around $520$ $"kJ"$ .