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Answer 1 · 2017-03-17T10:56:55

The ratio is $=0.54$

Let

mass of plane $=mkg$

speed of plane $=vms^-1$

radius of circle $=rm$

The centripetal force is $F=(mv^2)/r N$

The weight of the plane $W=mg N$

The ratio

$F/W=(mv^2)/r*1/(mg)$

$=v^2/(rg)=650^2/(80000*9.8)$

$=0.54$