Question #b5a9e

1 Answer
Nov 30, 2016

10 and 22 total 32 but have a difference of 12.

Explanation:

First, let's call our two numbers #x# and #y#.

We know from the problem:

#x + y = 32#

We also know:

#x - y = 12#

Next, solve the first equation for #x#:

#x + y - y = 32 - y#

#x + 0 = 32 - y#

#x = 32 - y#

Now we can substitute #32 - y# for #x# in the second equation and determine the value of #y#:

#(32 - y) - y = 12#

#32 - 2y = 12#

#32 - 32 - 2y = 12 - 32#

#0 - 2y = -2#

#-2y = -20#

#(-2y)/-2 = (-20)/(-2)#

#y = 10#

We can now substitute #10# for #y# in the solution for the first equation and calculate #x#:

#x = 32 - 10#

#x = 22#