Question

Question #6e801

Answer 1

Here's what I got.

Explanation:

Assuming that your solution contains `"1 g"` of solute in `"100 mL"` of solution, you can say that it has a `1%` mass by volume percent concentration, i.e. `"1% m/v"`.

A solution's mass by volume percent concentration is calculated by looking at how many grams of solute you get for every `"100 mL"` of solution.

In this case, you know that `"100 mL"` of solution contains `"1 g"` of solute, so its mass by volume percent concentration will be `"1% m/v"`.

How about a solution that contains `"1 g"` of solute in `"50 mL"` of solution, what would its mass by volume percent concentration be?

`100 color(red)(cancel(color(black)("mL solution"))) * overbrace("1 g solute"/(50color(red)(cancel(color(black)("mL solution")))))^(color(blue)("known composition")) = "2 g solute"`

This means that the solution is `"2% m/v"`, since it contains `"2 g"` of solute for every `"100 mL"` of solution.