Question

Question #25959

Answer 1

2.34 gram

Explanation:

Balanced equation:
`Pb(NO3)2(aq) + 2NaCl(aq) -> PbCl2(s) + 2NaNO3(aq)`

And as for the "the percentage formed weighed 5.56g" part of the original question...

I'm going to assume that you mean the precipitate, `PbCl2(s)` weighs 5.56 gram.

I can see that you would like to know the mass of `NaCl`.
Let's use the molar ratios from the balanced chemical equation to calculate the mass of `NaCl`

Consider below: