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Question #7037e

1 Answer

Dec 5, 2016

At standard temperature and pressure:
$16 A l (s) + 3 S_{8} (s) \to 8 A l_{2} S_{3} (s)$ $16Al (s) + 3S_8(s) -> 8Al_2S_3 (s)$

Explanation:

See above. Aluminum(III) Sulfide is $A l_{2} S_{3}$ $Al_2S_3$ which is also solid at standard temperature and pressure.

We know that the suflide ion has a charge of $2 -$ $2-$ , and we are told aluminum has a charge of $3 +$ $3+$ . The above formula is the only option.

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