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Question #6fd64

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Dec 7, 2016

Use the factor-label method (a.k.a. Dimensional Analysis):

$\frac{2226 kJ}{1 mole} \frac{1 mole}{342 g} \frac{1000 g}{1 kg}$ $(2226" kJ")/(1 " mole") (1" mole")/(342" g")(1000" g")/(1" kg")$

Cancel the units:

$(2226" kJ")/(1cancel(" mole")) (1cancel(" mole"))/(342cancel(" g"))(1000cancel(" g"))/(1" kg")$

Perform the multiplication and division:

$(2226" kJ")/(1cancel(" mole")) (1cancel(" mole"))/(342cancel(" g"))(1000cancel(" g"))/(1" kg") = 6509"kj"/"kg"$

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