Question #56a0e

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Answer 1 · 2016-12-11T22:08:29

$-1 <= x<1 and 1 < x<2$

1) $x+1>=0 color(red)((sqrt(x+1)))$

2) $2-x>0 color(red)(log(2-x))$

3) $log(2-x)!=0 color(red)(1/log(2-x))$

$x >= -1 and x<2 and 2-x!=1$

$x>= -1 and x<2 and x!=1$

that's

$-1 <= x<1 and 1 < x<2$