Question #e5a65

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Question #e5a65

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Answer 1 · 2017-01-12T20:46:20

$5^{t h}$ $5^(th)$ x-intercept is at $x = 5$ $x=5$ [or at $(x, y) = (5, 0)$ $(x,y)=(5,0)$ ]

Explanation:

The graph of $sin (θ)$ $sin(theta)$ crosses the X-axis at every integer multiple of $π$ $pi$
enter image source here

The $5^{t h}$ $5^(th)$ time (after and excluding the origin) the sine curve crosses the X-axis will be at $θ = 5 π$ $theta=5pi$

Replacing $θ$ $theta$ with $x π$ $xpi$
we have that the $5^{t h}$ $5^(th)$ crossing will happen when $x π = 5 π$ $xpi=5pi$ ;
that is, when $x = 5$ $x=5$

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