Question #ecc32

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Question #ecc32

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Answer 1 · 2016-12-14T13:40:58

$y - 5 = \frac{2}{3} (x + 2)$ $y - 5 = 2/3(x + 2)$ or $y = \frac{2}{3} x + \frac{19}{3}$ $y = 2/3x + 19/3$

Explanation:

We can use the point-slope formula to solve this problem. The point-slope formula is:

$y - y_{1} = m (x - x_{1})$ $color(red)(y - y_1 = m(x - x_1))$

Where $m$ $m$ is the slope, which for this problem is 2/3 and $(x_{1}, y_{1})$ $(x_1, y_1)$ is a point on the line, which for this problem is (-2, 5).

Substituting gives:

$y - 5 = \frac{2}{3} (x - - 2)$ $y - 5 = 2/3(x - -2)$

$y - 5 = \frac{2}{3} (x + 2)$ $y - 5 = 2/3(x + 2)$

or, solving for $y$ $y$ to put the equation in slope-intercept for is:

$y - 5 = \frac{2}{3} x + 2 \cdot \frac{2}{3}$ $y - 5 = 2/3x + 2 * 2/3$

$y - 5 = \frac{2}{3} x + \frac{4}{3}$ $y - 5 = 2/3x + 4/3$

$y - 5 + 5 = \frac{2}{3} x + \frac{4}{3} + 5$ $y - 5 + 5 = 2/3x + 4/3 + 5$

$y - 0 = \frac{2}{3} x + \frac{4}{3} + (\frac{3}{3} \cdot 5)$ $y - 0 = 2/3x + 4/3 + (3/3 * 5)$

$y = \frac{2}{3} x + \frac{4}{3} + \frac{15}{3}$ $y = 2/3x + 4/3 + 15/3$

$y = \frac{2}{3} x + \frac{19}{3}$ $y = 2/3x + 19/3$

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Question #ecc32

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