How many moles of "NaCl"NaCl are in 58.5 g of "NaCl"NaCl?

1 Answer
Jun 30, 2017

There is 1,00 mol of "NaCl"NaCl.

Explanation:

M_text(r) ("NaCl") = A_text(r) ("Na") + A_text(r) ("Cl") = "23 + 35,5" = "58,5"Mr(NaCl)=Ar(Na)+Ar(Cl)=23 + 35,5=58,5

So, 1 mol of NaCl has a mass of 58,5 g.

"Moles of NaCl" = "58,5" color(red)(cancel(color(black)("g NaCl"))) × "1 mol NaCl"/("58,5" color(red)(cancel(color(black)("g NaCl")))) = "1,00 mol NaCl"