5sqrt(3^2cdot 2)+3sqrt(2^2cdot 3)+4sqrt(3^2cdot 3) = 5√32⋅2+3√22⋅3+4√32⋅3= ?

1 Answer
Cesareo R.
Dec 14, 2016

3(5sqrt(2)+6sqrt(3))3(5√2+6√3)

Explanation:

5sqrt(3^2cdot 2)+3sqrt(2^2cdot 3)+4sqrt(3^2cdot 3) = 5√32⋅2+3√22⋅3+4√32⋅3=
5 cdot 3 sqrt(2)+3cdot2sqrt(3)+4cdot3sqrt(3)=5⋅3√2+3⋅2√3+4⋅3√3=
15sqrt(2)+6sqrt(3)+12sqrt(3)=15sqrt(2)+18sqrt(3) =15√2+6√3+12√3=15√2+18√3=
=3(5sqrt(2)+6sqrt(3)) =3(5√2+6√3)

Related questions
See all questions in Simplification of Radical Expressions
Impact of this question
1246 views around the world
You can reuse this answer
Creative Commons License