Question #81787

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Answer 1 · 2016-12-19T17:11:39

Range = $sf(1019color(white)(x)m)$

$sf(T=14.4color(white)(x)s)$

MFDocs

To get the time of flight T use:

$sf(v=u+at)$

To get the time t to reach the maximum height, take vertical components of motion:

$sf(0=vsintheta-"gt")$

$:.$ $sf(t=(vsintheta)/g=(100sin45)/9.81=7.208color(white)(x)s)$

Since the motion is symmetrical we can say that the total time of flight T will be given by:

$sf(T=2t=2xx7.208=14.41color(white)(x)s)$

To get the range use the horizontal component of velocity which is constant.

$sf(s=vcosthetaxxt)$

$:.$ $sf(s=100cos45xx14.41=1019color(white)(x)m)$