Question #85711

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Answer 1 · 2017-01-18T01:41:03

$r=(23*5)/(x+7)=115/(x+7) => r^2=115^2/(x+7)^2=13225/(x^2+14x+49)$
$=(23^2*5^2)/(x+7)^2$

$r=(23*5)/(x+7) => r^2=((23*5)/(x+7))^2=(23*5)^2/(x+7)^2=((23)^2(5)^2)/((x+7)(x+7))$

$=((20+3)^2(25))/(x*x+7x+7x+7(7))$

$=(((20)(20)+(3)(20)+(3)(20)+(3)(3))(25))/(x^2+14x+49)$

$=((400+60+60+9)(25))/(x^2+14x+49)$

$=((400+120+9)(25))/(x^2+14x+49)=((529)(25))/(x^2+14x+49)$

$=((529)(20+5))/(x^2+14x+49)=(529(20)+529(5))/(x^2+14x+49)$

$=(2(5290)+5290(1/2))/(x^2+14x+49)=(10580+2645)/(x^2+14x+49)$

$13225/(x^2+14x+49)$