Question #dabf9

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Answer 1 · 2017-01-26T17:44:01

The real part is $=5/13$

We need

$(a-b)(a+b)=a^2-b^2$

$i^2=-1$

The conjugate of $(a+ib)$ is $(a-ib)$

We multiply numerator and denominator by the conjugate of the denominator

$((4-i)(2-3i))/((2+3i)(2-3i))=(8-12i-2i+3i^2)/(4-9i^2)$

$=(5-14i)/(13)$

$=5/13-14/13i$

The real part is $=5/13$