Question #81fe9

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Question #81fe9

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Answer 1 · 2016-12-30T01:58:20

(see below)

Explanation:

Consider the relationship between decreasing powers of any number.

If we let $n$ $n$ be such a number then we see that (for example):
$XXX n^{4} = n^{5} \div n$ $color(white)("XXX")n^4 = n^5 div n$

$XXX n^{3} = n^{4} \div n$ $color(white)("XXX")n^3 = n^4 div n$

$XXX n^{2} = n^{3} \div n$ $color(white)("XXX")n^2 = n^3 div n$

$XXX n^{1} = n^{2} \div n$ $color(white)("XXX")n^1 = n^2 div n$

if we continue...
$XXX n^{0} = n^{1} \div n$ $color(white)("XXX")n^0 = n^1 div n$ (n.b. this is just $n \div n = 1$ $ndivn=1$ )
and
$XXX n^{- 1} = n^{0} \div n$ $color(white)("XXX")n^(-1) = n^0 div n$ (that is $1 \div n = \frac{1}{n}$ $1divn = 1/n$ ; the reciprocal of $n$ $n$ )

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Question #81fe9

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