How many molecules are present in a $27*g$ mass of $OF_2(g)$ ?

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Answer 1 · 2016-12-30T20:01:59

$"Number of molecules"$ $-=$ $"Number of moles"xxN_A$ ......

Where $N_A="Avogadro's number"$ $=$ $6.022xx10^23*mol^-1$

$"Number of moles"$ $=$ $"Mass"/"Molar mass"$

$=$ $(27*g)/(54.00*g*mol^-1)=0.500*mol$

And thus $"Number of molecules"$ $=$ $6.022xx10^23*mol^-1$

$=$ $3.011xx10^23$ $OF_2$ molecules..........

What is the oxdation number of oxygen in this molecule?

How many molecules are present in a 27*g27*g mass of OF_2(g)OF_2(g)?