Question #de290

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Answer 1 · 2017-01-03T04:57:54

$x = \frac{2}{3}$ $x=2/3$ or $x = - 2 \frac{1}{2}$ $x=-2 1/2$

$6 x^{2} + 11 x = 10$ $6x^2+11x=10$

Subtract $10$ $10$ from each side.

$6 x^{2} + 11 x - 10 = 0$ $6x^2+11x-10=0$

Factorise.

$6 x^{2} + 15 x - 4 x - 10 = 0$ $6x^2+15x-4x-10=0$

$3 x (2 x + 5) - 2 (2 x + 5) = 0$ $3x(2x+5)-2(2x+5)=0$

$(3 x - 2) (2 x + 5) = 0$ $(3x-2)(2x+5)=0$

$3 x - 2 = 0$ $3x-2=0$ or $2 x + 5 = 0$ $2x+5=0$

$x = \frac{2}{3}$ $x=2/3$ or $x = - \frac{5}{2} = - 2 \frac{1}{2}$ $x=-5/2=-2 1/2$