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Answer 1 · 2017-01-07T14:00:23

The balanced equation of the reaction for the preparation of ethyne ( $C_2H_2$ ) by the action of water on $CaC_2$ is as follows.

$CaC_2+H_2O->=Ca(OH)_2+C_2H_2$

As per above equation 1 mol $C_2H_2$ is produced from 1 mol $CaC_2$ .

Molar mass of $CaC_2=(40+2*12)=64g/"mol"$

The given amount of $CaC_2=20g=20/64mol=5/16mol$ .

So the amount of ethyne $C_2H_2$ produced $=5/16mol$ .
The molar mass of ethyne $C_2H_2=2xx12+2xx1=26g/"mol"$ .

So the mass of ethyne $C_2H_2$ produced

$=5/16molxx26g/"mol"=8.125g$ .