Question #3127e

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Answer 1 · 2017-01-10T20:04:19

$b = (cd -ac)/(a-d-ac)$

The problem is that there is more than one term with $b$ .

Remove the brackets:

$a(b+c) -d(b+c) = abc$

$color(blue)(ab) + ac color(blue)(-bd) -cd = color(blue)(abc)" "larr$ move all 'b' terms to one side

$color(blue)(ab -bd -abc) = -ac +cd" "larr$ Factor out 'b'

$color(red)(b)(a-d -ac) = -ac +cd" "larr$ there is now only one 'b'

$color(red)(b) = (cd -ac)/(a-d-ac)" "larr$ divide to isolate 'b'