If $pOH=10.75$ , what is the concentration of $[HO^-]$ in the solution?

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Answer 1 · 2017-01-10T16:38:24

$[HO^-]=1.78xx10^-11*mol*L^-1.$

$pOH=-log_10[HO^-]$

If $pOH=10.75$ , then $[HO^-]=10^(-10.75)=1.78xx10^-11*mol*L^-1.$

What are $pH$ , and $[H_3O^+]$ in this solution?

If pOH=10.75pOH=10.75, what is the concentration of [HO^-][HO^-] in the solution?