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Answer 1 · 2017-01-16T13:24:16

Molar mass of
#"Fe"_2"O"_3=(2xx56+3xx16)g"/mol"=160g"/mol"#

So #160g" "Fe_2O_3# contains #112g" " Fe#

Hence #160"tonne "Fe_2O_3# contains #112"tonne " Fe#

#"Fe"_2"O"_3(s) + 3"CO"(g) -> 2"Fe"(l) + 3"CO"_2(g)#

As per the given balanced equation 160 g of #Fe_2O_3# produces 112 g #Fe# on reduction.

So 112tonnes of iron can be obtained by reducing 160 tonnes of iron (III) oxide.