Question

Question #a54b1

Answer 1

Memorize this definition: The average rate of change of a function `f` on interval `[a,b]` is `(f(b)-f(a))/(b-a)`

Explanation:

Now apply the definition

The average rate of change you've been asked for is

`(g(b)-g(2))/(b-2) = ([3b-4]-[3(2)-4])/(b-2)`

Now use algebra to simplify.

`= (3b-4-2)/(b-2)`

`= (3b-6)/(b-2)`

`= (3(b-2))/(b-2)`

`= (3cancel((b-2)))/cancel(b-2)`

`= 3`