Question #85ef8

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Question #85ef8

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Answer 1 · 2017-01-13T03:25:25

You first work out the molar mass of potassium sulfide.

Explanation:

The molecular formula is $K_{2} S$ $K_2S$ so we add the atomic masses from the periodic system chart:
$m (K_{2} S) = m (K) + 2 \times m (S) = 39.10 + 2 \times 32.07 = 103.24$ $m(K_2S)=m(K)+2xxm(S)=39.10+2xx32.07=103.24$
If we take this in grams, we have one mol (or mole).

So 5.8 mol would be $5.8 \times 103.24 \approx 599 g$ $5.8xx103.24~~599g$

If we take care of the 2 significant digits in the 5.8, AND use the SI-unit, the answer would be $0.60 k g$ $0.60kg$ In grams it would be $6.0 \times 10^{2} g$ $6.0xx10^2g$

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Question #85ef8

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