How many $"microns"$ are in a $0.056915*m$ length?

Question

1594 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-13T07:42:42

$1*m-=10^6mum$ , i.e. $mu=xx10^-6$

And thus $0.056915*m$ $=$ $(0.056915*cancelm)/(10^-6*cancelm*mum^-1)$

$=56195*(1)/(mum^-1)==56195*(1)/(1/(mum))=56195*mum.$

Note that when use a calculator (which of course I did!), when you put in the exponential $"1 exp 6"$ , this is actually $1xx10^6$ . Claro?

How many "microns""microns" are in a 0.056915*m0.056915*m length?