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Answer 1 · 2017-01-16T16:28:23

Approx. $0.029 \cdot m o l$ $0.029*mol$ of benzene.................And the number of moles is equal to the number of benzene molecules.

We need to find the molar quantity of benzene, and thus we simply perform the operation:

$\frac{Mass}{Molar mass of benzene}$ $"Mass"/"Molar mass of benzene"$ to give an answer in moles, $=$ $=$

$(2.24*cancelg)/(6xx12.011*cancelg*mol^-1+6xx1.00794*cancelg*mol^-1)$

$=0.0287*mol$ .

Note that this is dimensionally consistent, because, $1/("mol"^-1)=1/(1/"mol")="mol"$

So there are $0.0287*mol$ of benzene $"molecules"$ .

And since $1*mol-="Avogadro's number of molecules"$ $=$ $6.022xx10^23*mol^-1$

And $=0.0287*mol*"benzene molecules"xx6.022xx10^23*mol^-1="How many benzene molecules?"$

And $"how many atoms?"$ , $=0.0287*molxx12*"atoms"*mol^-1xx6.022xx10^23*mol^-1="How many atoms?"$

Why did I need to multiply the molar quantity by $"12 atoms?"$