Under a pressure of $1.2atm$ a gas occupies an $8mL$ volume in a piston. What pressure develops if the volume is increased to $12*mL$ ?

Question

1834 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-16T21:22:43

$P_2=0.8*atm$

Boyle's Law holds that $P_1V_1=P_2V_2$ at constant temperature.

And thus $P_2=(P_1V_1)/V_2=(1.2*atmxx8*mL)/(12*mL)=0.8*atm$ .

This decrease in pressure is reasonable, given that we have INCREASED the volume.

Under a pressure of 1.2*atm1.2*atm a gas occupies an 8*mL8*mL volume in a piston. What pressure develops if the volume is increased to 12*mL12*mL?