Question

What is the concentration of potassium sulfate when a `0.65*mol` quantity is dissolved in `2.5*L` of aqueous solution?

Answer 1

`[K_2SO_4]=0.26*mol*L^-1`

Explanation:

By definition, `"molarity"="Moles of solute"/"Volume of solution"`

And thus `[K_2SO_4(aq)]=(0.65*mol)/(2.5*L)=0.26*mol*L^-1`; what are the concentrations of this solution with respect to (i) `SO_4^(2-)` ion, and (ii) `K^+` ions?

What is the concentration with respect to potassium sulfate in `g*L^-1`?