Question #507b8

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Question #507b8

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Answer 1 · 2017-01-26T01:13:39

This is $0.535$ $0.535$ mol of $H_{2}$ $H_2$ molecules

Explanation:

Since a mole of any objects is $6.02 \times 10^{23}$ $6.02xx10^(23)$ of those objects, we need only divide the given quantity by this value (known as Avogadro's constant).

$\frac{3.22 \times 10^{23}}{6.02 \times 10^{23}} = 0.535 m o l$ $(3.22xx10^(23))/(6.02xx10^(23))=0.535 mol$

(The fact that the question refers to $H_{2}$ $H_2$ molecules does not affect the calculation at all.)

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Question #507b8

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