What mass of oxygen is required to make 90*g90⋅g of NONO?

1 Answer
anor277
Jan 26, 2017

Approx. 42*g42⋅g

Explanation:

We could assume either atoms or molecules; for this problem it is wise to use atomic mass.

"Atoms of oxygen"-=(48*g)/(16.00*g*mol^-1)=3.0*mol*"oxygen atoms, i.e "3xxN_A" oxygen atoms."Atoms of oxygen≡48⋅g16.00⋅g⋅mol−1=3.0⋅mol⋅oxygen atoms, i.e 3×NA oxygen atoms.

So we need 3.0*mol3.0⋅mol "nitrogen atoms"nitrogen atoms, or 3xxN_A3×NA "nitrogen atoms,"nitrogen atoms, which has an equivalent mass of,

3*molxx14.01*g*mol^-1=??*g3⋅mol×14.01⋅g⋅mol−1=??⋅g

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