How many moles are present in $7.25xx10^25$ $"carbon dioxide molecules"$ ?

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Answer 1 · 2017-02-02T14:31:47

Well one mole of stuff, any stuff, including carbon dioxide, specifies $6.022xx10^23$ individual items of that stuff.

And thus we work out the quotient:

$(7.2xx10^25*"carbon dioxide molecules")/(6.022xx10^23*"carbon dioxide molecules"*mol^-1)$

$~=120*mol$ $"carbon dioxide"$ .

This is dimensionally consistent, because we get an answer with units $1/(mol^-1)=1/(1/"mol")=mol$ as required.

Do you agree?

What is the mass of this quantity of carbon dioxide?

How many moles are present in 7.25xx10^257.25xx10^25 "carbon dioxide molecules""carbon dioxide molecules"?