What is the $"molar concentration"$ of a mass of $21.9g$ mass of $"potassium chloride"$ dissolved in $869mL$ of solution?

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Answer 1 · 2017-02-03T16:15:45

$"Molarity"$ $=$ $"Moles of solute"/"Volume of solution"$

And so we just have to plug the given numbers in, knowing that $"potassium chloride"$ has a molar mass of $74.55*g*mol^-1$ .

$"Molarity"$ $=$ $((21.9*g)/(74.55*g*mol^-1))/(0.869*L)~=0.3*mol*L^-1$ .

Note that $1*mL=10^-3L$ ; equivalently, $1000*mL-=1.000*L$ . What are the concentrations with respect to $K^(+)(aq)$ and $Cl^(-)(aq)$ ?

What is the "molar concentration""molar concentration" of a mass of 21.9*g21.9*g mass of "potassium chloride""potassium chloride" dissolved in 869*mL869*mL of solution?