What mass is associated with a $17.8*mL$ volume of aluminum metal?

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Answer 1 · 2017-06-17T07:31:27

This site reports that $rho_"Al"=2.7*g*cm^-3$

We know that $rho$ , $"density"="unit mass"/"unit volume"$

And thus $"mass"="density"xx"volume"$

And thus, since $1*mL-=1*cm^3$ , we take the product........

$"volume"xx"density"="mass"$

So $"mass"=rhoxx"volume"$

$=2.7*g*cancel(mL^-1)xx17.8*cancel(mL)=48*g$

The given product is dimensionally consistent. We want an answer in grams, and the product gives us an answer in grams.

What mass is associated with a 17.8*mL17.8*mL volume of aluminum metal?