Successive numbers starting from 1 are written in a rectangular grid, starting in the top left corner and snaking down diagonally to the right as shown. In which row and column does 2008 occur?

01002006007015016
030050080140etc
04009013
10012
11

1 Answer
Feb 6, 2017

The 9th row, 55th column.

Explanation:

The last number added to the nth (reverse) diagonal is the nth triangular number Tn=12n(n+1).

What is the smallest triangular number greater than or equal to 2008?

Given:

12n(n+1)=Tn2008

Multiply both ends by 2 to get:

n(n+1)4016

So the value of n we are looking for is roughly 401663 and we find:

T63=126364=2016

T62=126263=1953

So 2008 lies on the reverse diagonal which has T63=2016 at one end.

Note that due to the boustrophedonic (like an ox ploughing a field) way in which the numbers are written, T63 will be written on the top row as the 63rd term of that row.

2008 will occur 8 rows below and to the left of it, i.e. on the 9th row in the 55th column.