Question #7cc9a

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Answer 1 · 2017-02-07T00:17:38

$x=3$

$2ln(x-2) - ln(2x-5) = 0$

$=> ln((x-2)^2) - ln(2x-5) = 0$

$=> ln((x-2)^2) = ln(2x-5)$

$=> e^ln((x-2)^2) = e^ln(2x-5)$

$=> (x-2)^2 = 2x-5$

$=> x^2-4x+4 = 2x-5$

$=> x^2 - 6x + 9 = 0$

$=> (x-3)^2 = 0$

$:.x=3$