Find cos1xcos1y, if x=14 and y=23?

1 Answer

cos1(112(2+53))

Explanation:

Let z=cos1xcos1y then

cosz=cos(cos1xcos1y)

but cos(ab)=cosacosb+sinasinb so

cosz=cos(cos1x)cos(cos1y)+sin(cos1x)sin(cos1y)

but

cos(cos1x)=x and sin(cos1x)=1x2 so

cosz=xy+1x21y2

so

cosz=1423+1(14)21(23)2

= 16+151659=16+5123

= 112(2+53)

so z=cos1(112(2+53))