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Question #5f06f

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Jul 9, 2017

given $∣ ∣ \to a ∣ ∣ = 1 and ∣ ∣ ∣ \to b ∣ ∣ ∣ = 1$ $absveca=1 andabsvecb=1$ as $\to a and \to b$ $veca and vecb$ are unit vector

again
$∣ ∣ ∣ \to a \times \to b ∣ ∣ ∣ = \frac{1}{2}$ $abs(vecaxxvecb)=1/2$

=> $∣ ∣ \to a ∣ ∣ ∣ ∣ ∣ \to b ∣ ∣ ∣ sin θ = \frac{1}{2}$ $absvecaabsvecbsintheta=1/2$

=> $1 \cdot 1 \cdot sin θ = \frac{1}{2}$ $1*1*sintheta=1/2$

$\Rightarrow θ = \frac{π}{6}$ $=>theta=pi/6$

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