Question #fcd4f

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Answer 1 · 2018-01-08T09:47:34

Please see the process steps below...

$(x^2 + 12)/(x^2 + x) = 8 - x$

Cross multiply..

$(x^2 + 12)/(x^2 + x) = (8 - x)/1$

$(x^2 + 12) xx 1 = (8 - x) (x^2 + x)$

$x^2 + 12 = 8x^2 + 8x - x^3 - x^2$

$= 7x^2 + 8x - x^3$

Collecting like terms..

$7x^2 - x^2 + 8x - x^3 - 12 = 0$

$6x^2 + 8x -x^3 - 12 = 0$

Rearranging the polynomial (Multiplying through by $(-)$ ..

$x^3 - 6x^2 - 8x + 12 = 0$