What is the mass of a $1.26 \times 10^{- 4} \cdot m o l$ $1.26xx10^-4*mol$ quantity of acetic acid?

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What is the mass of a $1.26 \times 10^{- 4} \cdot m o l$ $1.26xx10^-4*mol$ quantity of acetic acid?

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Answer 1 · 2017-02-09T16:24:50

$In acetic acid,$ $"In acetic acid,"$ $H_{3} {CCO}_{2} H$ $H_3"CCO"_2H$ ?

Explanation:

Now, the basic equation is $moles$ $"moles"$ $=$ $=$ $\frac{mass}{molar mass}$ $"mass"/"molar mass"$ ....and thus $mass$ $"mass"$ $=$ $=$ $moles$ $"moles"$ $\times$ $xx$ $molar mass$ $"molar mass"$ .

So here,

$mass$ $"mass"$ $=$ $=$ $1.26xx10^-4*cancel(mol)xx60.05*g*cancel(mol^-1)=7.60*mg$ .

Certainly, this expression is dimensionally consistent. I wanted an answer with units of mass, and the calculation did in fact give such units.

Answer 2 · 2018-04-02T16:17:15

The mass of $"CH"_3"COOH"$ is $"0.00757 g"$ .

Explanation:

Multiply moles by molar mass.

The molar mass of acetic acid $("CH"_3"COOH")$ is $"60.052 g/mol"$ .
https://www.ncbi.nlm.nih.gov/pccompound?term=%22acetic+acid%22

$1.26xx10^(-4)color(red)cancel(color(black)("mol CH"_3"COOH"))xx(60.052"g CH"_3"COOH")/(1color(red)cancel(color(black)("mol CH"_3"COOH")))="0.00757 g CH"_3"COOH"$ (rounded to three significant figures)

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What is the mass of a $1.26 \times 10^{- 4} \cdot m o l$ $1.26xx10^-4*mol$ quantity of acetic acid?

2 Answers

Explanation:

Explanation:

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What is the mass of a 1.26xx10^-4*mol1.26×10−4⋅mol1.26xx10^-4*mol quantity of acetic acid?

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What is the mass of a $1.26 \times 10^{- 4} \cdot m o l$ $1.26xx10^-4*mol$ quantity of acetic acid?