Question #487c5

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Answer 1 · 2017-07-08T11:54:15

$x approx 26.7$ $"in"$

The two triangles in the image are "similar triangles".

So, corresponding sides should be in the same ratio:

$Rightarrow frac(45 " in")(30 " in") = frac(40 " in")(x)$

$Rightarrow 1.5 = frac(40 " in")(x)$

$Rightarrow 1.5 x = 40$ $"in"$

$Rightarrow x = 26.666...$ $"in"$

$therefore x approx 26.7$ $"in"$

Therefore, the unknown side has a length of approximately $26.7$ $"in"$ .