Question

Solve the equation `5^x=4^(x+1)`?

Answer 1

`x=6.213`

Explanation:

As `5^x=4^(x+1)`, taking logarithm on both sides we get

`xlog5=(x+1)log4`

or `x(log5-log4)=log4`

or `x=log4/(log5-log4)`

or `x=log4/log(5/4)`

or `x=log4/log1.25=0.60206/0.09691=6.213`